Aptitude¶
Percentage¶
percentage change
by what percent is x more/less than y
\(\%=\dfrac{x-y}{y}\times 100\)
15% increase in x or 15% more than x
fundamental
x + (15% of x )
\(=x + (\frac{15}{100} \times x )\)
\(=x+0.15x\)
\(=1.15x\)
quick
\((1+0.15)x\)
\(1.15x\)
15% decrease in x or 15% less than x
fundamental
x - (15% of x )
\(=x - (\frac{15}{100} \times x )\)
\(=x-0.15x\)
\(=0.85x\)
quick
\((1-0.15)x\)
\(=0.85x\)
200% increase in x or 200% more than x
fundamental
x + (200% of x )
\(=x + (\frac{200}{100} \times x )\)
\(=x+2x\)
\(=3x\)
quick
\((1+2)x\) \(=3x\)
successive percentage
x % of y
examples
% increase
1.1x = 10% increase in x
1.2x = 20% increase in x
% decrease
0.8x = 20% decrease in x
0.2X = 80% decrease in x
Logarithms¶
if \(log_a(x)=y\) then, x=?
\(\boxed{x = a^y}\)
\(log_a(x) \ne x \cdot log(a)\)
\(log_a(m \times n)\)
\(= log_a(m) + log_a(n)\)
\(\neq log_a(m + n)\)
\(log_a(\frac{m}{n})\)
\(= log_a(m)- log_a(n)\)
\(\neq log_a(m-n)\)
\(log_a(x^m)\)
\(= m\cdot log_a(x)\)
\(log_{a^n}(x)\)
\(=\frac{1}{n}log_a(x)\)
\(log_a(1)\)
\(=0\)
\(log_a(a)\)
\(=1\)
\(a^{log_a(x)}\)
\(=x\)
\(a^{\frac{1}{n}}\)
\(a^{\frac{1}{n}} = \sqrt[n]{a}\) = \(n^{th} \text{ root of a}\)
\(a^{\frac{1}{2}} = \sqrt[2]{a}\)
\(a^{\frac{1}{3}} = \sqrt[3]{a}\)
SI-CI¶
CI
\(\text{amount}=P(1+\frac{r}{100} )^n\)
\(\text{CI}=A-I= P(1+\frac{r}{100} )^n -P\)
\(\text{CI}\ne P(1+\frac{r}{100} )^n\)
CI = CI in this year - CI of previous Year
Difference CI-SI for 2 years
\(CI-SI=\color {green}P(\frac{r}{100})^2\)
Difference CI-SI for 3 years
\(CI-SI=\color {green}P(\frac{r}{100})^3 + 3P(\frac{r}{100})^2\)
Permutation And Combination¶
Permutation
\(^nP_r=^nC_r\times R!\)
\(^nC_{r-1}+^nC_r=^{n+1}C_r\)
\(\binom{n}{r}\)
\(=\frac{n!}{(n-r)!r!}\)
properties of \(\binom{n}{r}\)
\(\binom{n}{r}=\binom{n}{n-r}\)
\(\binom{n}{0}=1\)
\(\binom{n}{1}=n\)
\((a + b)^n\)
\(= \binom{n}{0}a^{n}b^{0} +\binom{n}{1}a^{n-1}b^{1}+\binom{n}{2}a^{n-2}b^{2}+...+\binom{n}{n-1}a^{1}b^{n-1}+\binom{n}{n}a^{0}b^{n}\)
Number System¶
\(N = a^p b^q c^r\)
number of factors of N
=(p + 1) (q + 1) (r + 1)
can be expressed as the product of two factors in
1/2 {(p + 1) (q + 1) (r + 1)} ways
if N is a perfect square, it can be expressed
as a product of two DIFFERENT factors in
1/2 {(p + 1) (q + 1) (r + 1) - 1 } ways
as a product of two factors in
1/2 {(p + 1) (q + 1) (r + 1) +1} ways
LCM × HCF
= product of two numbers
\(\sum\limits_{k=1}^{n} k=1^1 + 2^1 + 3^1 + … + n^1\)
\(= \dfrac{n(n + 1)}{2}\)
\(\sum\limits_{k=1}^{n} k^2=1² + 2² + 3² + … + n²\)
\(= \dfrac{n ( n + 1 ) (2n + 1)} { 6}\)
\(1³ + 2³ + 3³ + …+ n³\)
\(= \Big(\dfrac{n(n + 1)}{ 2}\Big)^2\)